SSC CGL 2024 Maths| Police & Thief Concept & Questions of SSC CGL 2023

Hello everyone, I hope you all are healthy, our series is going on in which I am giving you all the maths questions of SSC CGL 2023 Tier One, chapter wise with concepts, within that the topic we have taken today is Thief Police . Questions related to Police and Thief are asked in time speed exam. Generally, so many questions were not asked in exams but in CGL 2023 year, total 22 23 questions were asked only on the concept of Police and Thief, which is a small concept in speed. Which we study, th

en I will tell all the questions with type wise concept in this video, so you will not get any question related to this and even if you face any problem in the exams, it is okay because in this there is a small section of each type. It is inserted and everything will be clear to you. If you already know this concept then you will move ahead a little in the video. You can start from question one because in the beginning I will take you for the concept in five minutes. Okay, rest in the same way.

We have uploaded many videos on the channel in which a complete series is going on in which I am providing chapter wise solutions of CGL 20 23. You can also watch the other chapters there and I have given a crash course on Time Speed ​​and Distance. The video is included separately in the playlist of Maths Crash Course, which is a very important video of one and a half hour, you can watch it if you want to study time, speed and distance and a video of the race is also included separately below i

t. You will get it, you can see, now I will not take much of your time and start my session, all these are free playlists, one is of rush course, rest of which is this, the playlist with solutions which was shown behind is fine and different. Course classes of different subjects will be available in PDF also, I will send it to you on Telegram, from there you will be able to see what is the concept of the question, like if we talk, if two persons come towards each other, then suppose we have what

? Is there a person ​What is the speed of How much will it run, it will run within R, it will go 3 kilometers, then from the distance between them, there would have been D distance between them, after one hour, when both of them will walk, then how much distance will be reduced, it is reduced by three from here and two from here. If it decreases, then the distance which is decreasing between them and within an hour is called our relative speed. So if I talk about relative speed, then what will b

e the relative speed of these two? How much distance will be decreased in one hour. And three pa is 2 p 3 5 kilometers, what are they doing? The distance between them is decreasing within an hour. If you want to tell the speed, then how much distance per time is this much distance is decreasing between them in one hour. So what is the relative speed in this case? When two persons are moving towards each other, what is the relative speed ? It becomes equal to both of them. If everyone understood

this part, then basically what can we say? How much is the distance between two objects decreasing within the given time? That is called our relative speed. If you are moving in the same direction, okay, now here comes another case. What is happening now? Both the persons are moving towards each other. Okay, sometimes it happens that both the persons are moving in the same direction, like this one is moving here and this one is also moving here, so in this particular case What will happen, I hav

e Person A and I have Person B, okay now I make a change, I assume his speed is R at 2 km and I have his speed R at 3 km and their The distance between them and still at the moment I have just written D. If there is no problem here then what will happen after one hour, in one hour it will go 3 km, within one hour it will go how much 2 km, then you tell me the distance between them. How much will that distance be? How much will be this distance? You will say, sir, earlier D was three, this one ha

s gone two, this one has gone two, so 1 kilometer 3 - 2, how much distance is left, distance between them is 3 - 2, after one hour, right. How much distance is being covered in one hour? Basically, how much is the distance covered by these two? How much is it decreasing? You will say, Sir, 3 This is what is called our relative speed, then what will be the relative speed that I have? You will say, Sir, these 3 minutes, because I am talking about one hour, so R is so many kilometers, so when two p

ersons move towards each other, what is their relative speed? From the speed of A, we will subtract the speed of BB and What will we call this or what is called relative speed? Now here you understand carefully that whenever we have two persons moving in the same direction, we will assume that the person who is behind will have more speed and the one who is in front will have less speed. It must be because somewhere, what is the person behind doing to the person in front, he must be accelerating

and we see the same case in the question of Police and Thief, that the thief has stolen and he starts running away. Is there any distance between them and what does the policeman do? He works to catch him. This much part is clear. Okay, now let me assume that there is distance between them. Okay, after how much time will the policeman catch the thief? I take the speed of the thief to be If the distance between them is D, then after how much time will the policeman catch the thief? You will say

Sir, D is the distance, the gap between them has to be closed. Relative speed x - y. With this speed, the gap between them is closing, then what is the speed in distance upon If there is time, what will become of me? After how much time will the policeman catch the thief? Is this much the portion? Have you all understood? I will try to explain it to you with a small example. A little more in this. I do the modification so that you can understand the question very well, what will happen. Suppose,

what I have, this is the question, I have a policeman, at what speed, a thief is moving at a speed of 3 kmph. The distance between them was increased to 6 km. When the policeman saw the thief for the first time, the thief was 6km ahead. The policeman started running. The thief started running at a speed of 3 km R. At a speed of 2 km R, after how much time will the policeman catch the thief? You will say sir, what will happen in one hour? In 1 hour, the policeman will run 3 kms and the thief wil

l run 2 kms. How much difference is reduced in 1 hour. If the total was six then 3 - 2 If the distance of 1 km is reduced then how much will have to be walked to cover the distance of 6 km. Will have to walk for 6 hours because the distance of 1 km is decreasing in 1 hour. So the distance of 6 km will be covered in 6 hours, we understood it orally, if I try to understand it from the formula then you will say sir, the distance between these two is 6 km, that distance is the speed of the policeman

, 3 km is the speed of the thief. I have 2 kilometers and the time that will come to me, after how many hours will the policeman be able to catch the thief, then 6 of us, 3 - 2, this will come to 6 hours or so, everyone has understood, okay, now more questions arise in this. In this, the question can arise that how much distance did the policeman cover when he catches the thief, then the distance that the policeman covers to catch the thief, then you will say, Sir, what is the speed of the polic

eman, the speed of the policeman is R at 3 km and how much time will the policeman run? He will run only for 6 hours. If I catch the thief then you will say Sir, it will be six seconds. If I have 6 ars, then it will be 18 km. How much will the policeman have to walk? To catch this thief, we will have to walk 18 km. If I try to tell you its formula, then what could be the formula ? You will say, Sir, the distance covered by the policeman is equal to what was the distance between the policeman and

the thief divided. By police speed minus speed of thief, speed of police in into, is this the same thing, I have the total distance which was between the policeman and the thief, if I do the speed of police minus the speed of thief, then this time has come, in how much time will the policeman reach the thief? If I catch him and put the speed of the police in it, then this will be the distance that the policeman had to cover. This simple formula to catch the thief is clear to everyone, well, man

y times in it it asks from where the theft took place. What will be the distance till the thief is caught, then generally we believe that from where the policeman will see, what will happen to us, from where the policeman will start catching, this will be the spot where the theft has taken place, so generally we also have that distance. Now we are going to see a lot of questions of this type, so what are the two or three small formulas I made you write, do you understand them well? We have come

to this and we can also see it in terms of fractions and I will tell you that too, for now you just remember this formula and if you remember it then we will solve the questions in seconds which are asked in the exam. If you had asked us that Come on, thief , the policeman is here. If the thief saw the policeman and started running, then how much distance did the thief travel before being caught by the court? How much distance did the thief travel before being caught by the policeman? Then you w

ill say, Sir, how much time did the thief take? First we will have to see that, then the time of the thief will also be generally the same, what is it called 6 hours, so here I will have this six and what was the speed of the thief at 2 km R, then the thief must have run 12 km, the thief ran away from here. 12 Km policeman ran away from here for 18 Kms and the distance between them was covered by 6 Kms, then both the persons will be found. Right now, let's not go too much on this. Now if I ask q

uestions, things will get cleared in a better way. I will also explain the concept in another way. For now, if you understand the formulas using the ratio method, then remember that, a case can also be made that when two persons are moving away from each other, it is okay, for example, One person is going this way, one person is going this way, then what will happen in this case, they will never meet when they are coming towards each other, even when two persons were coming towards each other, t

hey meet each other when both are in the same direction. If we are moving then if the person behind is at a higher speed then he will still reach this point by going somewhere else but if two persons are moving towards each other or away from each other then they will never meet. If we don't meet, then generally there is no question on this, but if we ask you about relative speed, then what will happen? Suppose I have a person A and a person B, who is going 2 km from here at the speed of R and t

his is mine at 3 km. If it is going at the speed of Parr, then you will say sir, what is the distance between them, now at what speed will it increase. Suppose the distance between them is d, how much has it covered after one hour, 2 kilometers, how much has it covered in one hour, 3 kilometers. So what happened after one hour, how much did the distance between them increase d P 2+ 3 So in this case also we have the same relative speed that the speed at which the distance between them is increas

ing is called relative speed. It is clear, let's go ahead, I have told you some small things, now we will quickly ask questions based on this, the first question is that a policeman near me saw a thief who was 600 meters ahead of him, it is okay if the policeman I have. If he moves at a speed of 10 km/h and the thief moves at a speed of 8 km/h then in how much time will the policeman catch the thief? How will you say, Sir, this is the police I have and what is this that I have, the thief? When w

e talk about the police and the thief, we will assume that both of them will walk in the same direction. Exactly what is the distance between them? The speed of the policeman is 600 meters. The speed of the thief is 10. If I have it, then how many? After time, if the policeman catches the thief, you will say, Sir, the thief will run here, the policeman will run away from here, and there will come a point where these two will meet, I consider this point as the point where these two policeman and

thief will meet and The policeman will catch the thief. Have you understood this much? If both of them are running in the same direction. If I implement the formula then how will I do it? I will say what is the distance between them? It is 600 meters, ok let the distance be. If I talk about speed, the policeman's is 10, the thief's is eight, so it becomes 10 - 8, but here this distance is in meter, it is in kilometer, it is in R, so I will have to write, then this will be the time at which these

two We will meet each other right now, the time that has been asked from us here has been asked in minutes only, so you will keep it carefully here, if the speed is given in kilometers but in R, then what will you do to convert it into minutes, you will say sir here. If we have 600 meters, then first I convert it into kilometers, then I will get this value of 0.6, this is 2 kilometers, R is ok, I will convert R into minutes, then what will I have to do, I will have to divide by 60 . And this si

x will go there and get multiplied and I will get this value. 18 minutes. Whatever will happen after 18 minutes, the police will catch the thief. This is the basic formula version with which I solved the question. You can also do it directly by ratio method. That's the thing, I teach you in time speed distance. If you have read then you will understand things. Okay, look at me, understand this thing carefully. How long will the policeman run for? To catch the thief, the thief would run till tea

time. The thief was here and from here, the thief would also have run till tea time because at this particular point when the distance between them is 600 meters, both of them are running away from the policeman and the thief. Police, sorry, the thief escaped from the police and the policeman ran after the thief, both of them ran till time and finally got the income. If what happened to me is that time becomes constant, then I would say that the distance will be directly proportional to the spee

d, right? Distance is directly proportional to speed, so what will be the ratio of speed? Its speed is 10, its speed is 8, so the speed ratio of the policeman and thief that I have is 10:8 or if you want, you can also write it as 45 54. So whatever is the ratio of speed, whatever is the ratio of distance, the same will be the ratio of their speed. I said on the contrary, whatever is the ratio of their speed, what will be the ratio of their distance, then it means that if the policeman is there,

how much will the policeman run here? Here, if four ratio distance is run, then the thief will run here, four ratio distance, then what will be the distance, I will have one ratio, one ratio will represent 600 meters, what will one ratio represent for 600 meters, then 5 ratio will represent what? 5 * 600 This will be 3000 meters which will be 3 km. What is meant is that the policeman will have to walk 3 kms to catch this thief. Well, what is the speed of the policeman at 10 kms. R then he has to

go 3 kms. Speed ​​of 10. What will be the time taken at the speed of R at 10 km, then if we look at these arcs then 3/1 R will come in minutes, if we convert it into 60 then it will come in 18 minutes. Look carefully, is it clear or not? Question to all the people. So this is our ratio method. Generally in this type of question, when we have to tell time only then there is no need to go to ratio method. When we have to tell dis, then in that case ratio method becomes more handy but if you have

to tell time. So you can do this directly from basic, I have explained to you the entire situation. If you had asked us here how much time will the policeman take for the entire journey and how much distance will the policeman have to cover, then we are here as I have asked here. By using this method, I got 3 kms, otherwise you would have said sir, after how much time the policeman is catching the thief, after 18 minutes the speed of the policeman is 10 kms, so here I have 18 minutes in 10 minut

es. To convert it into R, it is 60. So I have this distance of 3 km. The policeman will run this distance. To catch the thief, how much distance will the thief cover before being quoted? Then you will say, Sir, how much time will the thief's thief last? If I ran for 18 minutes, then the speed of the thief was 18/6. The speed of the thief was 8 kilometers per hour. If I put 8 in this, then what value will I get? Here if you cut it from three, then it will be six and this will come to 10 or aa. Th

is will be 20 and 48 will be 2.4 km. This value will be 2.4. Otherwise you could have also said that if the policeman ran 3 km, how much will the thief run? 600 meters less which was the distance between them, subtract 600 meters from 3 km. What would we have got even if we had given it ? We would have got 2.4 km. This is the whole concept. Now we do all the questions on this as best we can quickly. In the question it is said that there is a constable Ram who is 225 meters behind. Ram runs away

from the thief Somesh. 50 meter within a minute and Somesh runs 30 meters within a minute. After how much time will the constable Ram catch Somesh? Then you will say sir, what is the speed of Ram at 50 meters and that of Somesh at 30 meters? Minutes, what is the distance between them? 225 meters, so I will directly apply F. How much gap is there between them to find out the time. 25 meters, what will be the relative speed? Minutes at 50 meters, minutes at 30 meters, then minutes at 50 and minute

s at 30 meters and this also. I have it given in meter, so I will get the time directly in minutes here, it will be 20 225 times 20 minutes, now what is given in minutes here, we have 15, 11, 10 and 16, how much time will it take, only 11 minutes will be taken . Times again 5 times 20 minutes will be left. If you convert 5 times 20 minutes into seconds then multiply by 60 then it will be 3 11 minutes 15 seconds. My answer to this question will be clear so this is my answer. Now let us move on to

the next question. I say there is a thief who steals a forest at 3 mph and starts driving at a speed of 57 kmph. The thief who is discovered is discovered at 4 mph and the owner starts catching the thief . He gives a speed of 76 Kms with the ban and tells us at what time the thief will be caught. Now pay attention to this situation. If you understand, then you will not face any problem in asking the questions. I have time here, 3.3 A.P. What did the thief do? He stole, okay and he started runni

ng at the speed of 57 km R. What happened now? If the theft was discovered at 4 o'clock, then you will say. Sir, the thief would not have stopped , then as if he has committed theft, he will start running away, if he waits a little, then what is the time between 3 am and 4 am, if there is a gap of one hour, then the thief must have run away for an hour, so now at this time The thief will be here and the person who is going to catch him is the owner. See, the one in whose place the theft has take

n place will start from here. So, I can't say what is the distance between the thief and the person who is going to catch him. Will come because in one hour the police or the thief has already run away, so 1 in 57 * there is already a distance of 57 km between them, now he will start catching him from here, this is the position of the thief, this is the position of the person who is going to catch him. It tells in what time the thief will be caught, so now we will check from 4 o'clock, how much

time will it take, then if I calculate the time, the distance is 57 kilometers, the speed of the person who is going to catch is 76, the speed of the thief is 57, then this value will come to me. Pass 19 If you cut it then 3R will take three more hours After 4 o'clock when the thief will be caught Then four and three How much will it be 7M At 7M the thief will be caught Take care Do not PM quickly Now the second thing here is if you have this problem The question had to be asked directly, if it

had not been done then I would have said, look friend, three and four, I just have to keep in mind the time, three and four, there is a gap of one hour here, now there is a gap of one hour, then the thief will escape by one hour. What is the speed ? 57 So 1 in 57 * This is the distance that the other person has to cover extra to catch the thief. So the relative speed. If I look, what will be the relative speed ? 76 - 57 So this is the time I have. When the person starts catching the thief, then

how much time will it take to catch the thief? If you solve it from here then it will come to 3 hours, then we will say that if we add 3 hours to 4 m, then it will become 7 AI Hope Question All. It is clear to the people, the concept is clear, I move ahead to the next question . Now look at the question, what does it say? The policeman sees the one who is there, it is okay from a distance of 210 meters, the policeman starts catching him, the thief starts running away. Okay, the speed of the thie

f is 25 and the speed of the policeman is R at 32 kilometers, so we have to tell how much the thief will have to run, how much will the thief run before he is caught by the policemen or the policemen. Now how will we do it? Sir, after how much time will the policeman catch the thief? What is the distance? 210 meters and what will be the relative speed: 32 - 25. I will have 7. Keep in mind because it is in meters. This is kilometer but it is in R, so I can write 1/1000 to convert it into kilomete

r. What will happen after this much time, the policeman will catch the thief? We have been asked how much the thief will have run away when the policeman will catch him. So now the thief has also run for tea time, the policeman has also run for tea time, then you will directly say, sir, multiply it here, the time has come, multiply it by the speed of the thief, the speed of the thief has been given to us by 25. R on km we will get the distance which has been covered by the thief. If I solve this

then one zero will be deducted from one zero. If I cut from here it will come to four and I will get 3 from here. 3/ 4 kilometers will come, if I convert it into meters then 1000 will come to 3/4 inu, I will have 750 meters. One way is done, what is the other way, I can explain it to you again by making a diagram, with the ratio method you will say sir, this is the police. This is the one with me, I have a thief, the distance between them has been given as 210 meters, okay, what will happen fro

m here, the thief will also run for tea time and the policeman will run only for tea time and what will happen here, both of them will meet. We have to tell how much distance the thief covered. This distance I have to tell what will happen. Now see because both of them are running for a constant time t. Time is constant then I have distance will be directly proportional to speed which the policeman The speed I have is 32 and the speed of the thief is 25, so the ratio of distance will also be div

ided into 32 and 25, so I will say here that the distance covered by the policeman will be 32. And what will be the distance covered by the thief, this will be the ratio of 25 and what will be the remaining distance, if 25 is subtracted from 32 then the distance between these two will be Here I will have 7 ratios, 7 represents 210, so one ratio represents 30, so 25 25 * 30, this will be 750, so how much distance did the thief cover? 750 meters. I hope you all have understood this question well.

If we had asked how much distance the policeman covered, you would have said, Sir, the ratio would have been 32. If we had made it 32 * 25, then we would have got our value that is 960 meters. Let's move ahead, now we will see more similar questions, you can use any method, it is up to you, okay, it is easier to apply the formula directly, if you remember it, because we just have to put, we do not need to make any diagram etc. But if you want to do it by using the ratio method then there is no p

roblem. See what we have been given here. One is a thief and the policeman changes the other. The distance between these two is 3 kilometers. The speed of the policeman is 7 at 25 km. Hour is the speed of the thief at 60 km r is R. We have to tell how much distance the thief would have covered when the policeman catches the thief. So you will say first of all in how much time will he be caught. There is a distance of three kilometers between them. What is the relative speed? It will be 75 - 60 T

hat is 15 What will the policeman do after this much time Will he catch the thief Now the thief will also have run for this much time So we have to tell how much distance did the thief cover Before being caught So what is the speed of the thief It is 60 in . Question has been made to 60, I am finished, this is what is mine, the answer to this question is cut from 51 and 3 becomes 12, it is cleared. There is no need to make any diagram etc. You can find the answer by applying direct formula. If y

ou had used ratio method, how would you have done it? You would have come in the same situation again, I have this policeman here, I have this thief, the distance between them is 3 kilometers, the chief is running at a speed of 60, the policeman is running from whom at a speed of 75, both are constant for time t. If we run then this is also t time. This too will run for t time. If time becomes constant then what will be the ratio of distance. If it becomes constant then this ratio will be 75 the

n this ratio will be 60 with me. You will say sir take the difference of these two. If you take or convert it into ratios, then 5 ratios, this is the fifth ratio, so I would have this four ratios, this distance is five ratios, this distance is four ratios, so how much will this distance represent 1 and 1:3, then 4 4 * 3 12 Will represent Kimi, it is best, apply your formula and find out the answer. Don't think anything, don't use your brain too much. Next question to solve the question: I have a

thief who sees the police at a distance of 300 meters and starts running. He runs at a speed of 10 km R, the policeman immediately starts changing him, starts trying to catch him and runs away, at a speed of 12 km R, we have to tell how much distance the thief will run before being quoted. So you will say Sir, it is 300 meters, okay, what will be the relative speed, if it is 12 and 10, then at 2 km, R will be the relative speed, we have to tell the distance, which one should take care of now, l

ook, I am writing the unit, you have this R per kilometer, thief. How much distance did he cover before bang code? So what was the speed of the thief? I had the speed of the thief. Here I have 10 so R is at 10 km. This must be the same so I have this thief's distance which he covered before being quoted. Now You will see carefully here this R is on kilometer, if it is cut to kilometer then my answer will come in meter, we will convert whatever value will come, if we cut 300 from Rs, we will get

150, then 1 10 1500 will come to this. 1500 meter T E 1.5 decrease I hope question is clear to the next question In the question it is said that a policeman follows a thief who goes 1250 meters ahead of him, the thief moves at a speed of 10 kmph, the police moves at a speed of 10 kmph And the thief moves at a speed of R at 8 km. How much distance will the thief cover before being nabbed by the police? So it comes to 1250 a 10 - 82. And here if the thief is asked, then it is 8 because this is met

er, this is R at kilometer. So this will be cut from here. If I cut from here then this four will be 1250 meters into 4. 5000 meters is 5 kilometers. Question is over. Next question. We have the same question. We will try it in homework. Tell us your opinion about this question by commenting in the comment section. What is the answer? The next question is exactly the same. There is a distance of 400 meters between the police and the thief. Seeing the police, the thief starts running. The police

does not start running after the thief. The speed of the thief is 32. The speed of the police is 40, so relative. When the speed reached 8 then after this much time the police The one who will catch, this is in meters, this is in kilometers, but let's move ahead. We have to tell how much the thief will run before being quoted. So if this is the time of the thief, what will be the speed of the thief. I have given 32, so this is the distance I have. If you have asked in meters only, then look at k

ilometers, hours are cut from here, cut 4 and 14 * 4, 16 km, meters, 1600 meters, sorry, this is my answer, let's move ahead to the next question which was asked in your exam, it is exactly the same question. Comment. Tell us by commenting in the section. What will be the answer? You should not spend more than five to 10 seconds in this question. The next question will be exactly the same homework again. You have to tell its answer by commenting in the comment section. Now let us move on to the

next type. Now look here. What is it? What were you doing right now? The question was asked in a slightly different way. There is a policeman who starts chasing a thief who is 600 meters ahead of him. The speed of the policeman is R at 9 kilometers. The speed of the thief is R at 8 kilometers. So we have to tell at what distance the thief will be caught. Well, pay great attention to the language of the question. How far the thief ran will be a different thing and at what distance the thief will

be caught is a different thing. At what distance the thief will be caught, this means that What is the distance covered from the point where the policeman started running till he caught the thief? He is asking how much distance the thief ran. There will be talk about the distance covered by the thief, but at what distance was the thief caught? He is asking, it means how much distance did the policeman cover to catch him, we have to tell him, okay, so if I talk here, see how much time will the po

liceman take to catch the thief, what is the distance, 600, how much is the relative speed, 9. - This is R at 81 km, I have a meter, in this time the policeman will catch the thief. I asked us, 'The thief would be caught at a distance of'. After how much distance will the thief be caught? So, if the policeman has asked for the distance here, then I will say. Policeman's speed in intu Time has been given to us, this policeman's speed has been given to us so much, R on 9 km, so you will pay attent

ion to kilometer, R on km, because it is common, it will be deducted, so I will get 9 * 6 5400 meter kilometer. If I write it is 5.4 km then it is ok let's go ahead Next Question We have the same question, there is a distance of 400 meters between the police and the thief, the thief started running after seeing the policeman, the policeman runs at a speed of 10 km/ h. At what distance will the policeman catch the thief from the starting point at the speed of aa? If you want to tell the distance

of the policeman then you will say sir, what is the speed of the policeman, I have 12, how much time will it take to catch the thief, the distance between them is 400. What is the difference between meter and speed? 12 - 10 Okay, now here because I know that there is no need to write again and again, these units are coming in kilometers, this is also coming in kilometers, so the distance I will get will be deducted. If it is seen here in meter then it will become 2 to 2 se katu 6 6 4 24 2400 met

er that is 2.4 km. Can everyone do it directly? You will not have to write even this much in the exam. Next question we have, have a quick look. One who police says The thief sees the thief at a distance of 360 meters, both of them start running at the same time and the speed of the policeman and the thief is 8 and the speed of the policeman is 99.2 km/h. How much time should the policeman have to run? To catch the thief, you will say, Sir, what is the speed of the policeman? 99.2. Okay, what is

the gap between them? 360 What is the relative speed? I have 9.2 -88 that is 1.2. The question is over and this is because it is in meter. The answer will come in meters. Here, if we see, my point has been eliminated from the point, cut it by 12, it will come to 30, 92 in these, 3 will come to 276, so 2760 meters, this will be my answer to this question. Next question we have type three. There is a slight change, the whole thing is the same. A policeman notices the thief. At a distance of 300 m

eters, the thief starts running and the policeman also starts running behind him. The speed of the thief and the policeman is 8 and 9 kilometers . But we have given the hour, so we have to tell what will be the distance between them after three minutes. Now a little different question has been asked here that what will be their distance after three minutes of 3 kilometers. Okay, now you pay attention here when the police. When the person is chasing the thief, the distance between them is gradual

ly decreasing. Can you tell by how much the distance between them would have decreased in 3 kilometers? Will you say Sir, what is the relative speed, here the thief's is eight and the police's is nine, so the relative speed becomes 9. At 8 kilometers R is at this speed and we are deciding how much distance will be covered in a minute. So, by multiplying the time, I said speed. So what distance have I got from this, how much gap they have covered between them, it will be visible to me within 3 mi

nutes, so you can solve it here, distance is in meters, if you want, calculate it in meters. Otherwise, I calculate it in kilometers. Currently, if kilometers are in R, then this is 1 kilometer. If I convert R minutes into R, then I will get 3/60 and this will be kilometer. Kilometer is in meter. To convert it into meter, I will again convert it into 1000. If I can , I can say how many kilometers of distance did they cover in 3 minutes, how many meters of distance did they cover, this will be 20

here and if I subtract from here then this value will come to me 50 3 Within 3 minutes the distance between them is 50 meters and it has decreased. What was the distance before? It was 300 meters. Now the distance that will be left between them is 300 minus 50. The distance left will be 250 meters. I hope everyone understands this question. It 's ok, I can explain it once to those people whose basic is weak, look carefully at this thing, what I have here is a policeman and here I have a thief,

which is 300 meters. If the policeman is ahead , then the distance between them becomes 300 meters. If the policeman is walking at 9 kilometers with a speed of The policeman will go this much, the thief will go how much in 3 minutes, you will say sir, the speed of eight is 8 divided by 60, these 3 will go in 1 minute, this much will go, now because it is moving in this direction and this is moving in this direction, then the difference between these two. If I take it out, I will get the value of

how much the policeman moved extra from the thief and the difference between them, how much the policeman moved extra from the thief, what will he do to reduce this distance, then out of 300 he will reduce the distance, then my You will get the answer, it is the same thing, okay, so if I solve it then this value will be 50 meters and if I subtract 50 from 300 then this value will be 250 I hope it is clear, let me move ahead now to the next question. Similar type of question is that a thief saw

a policeman at 200 meters and the thief started running as soon as he saw him. The policeman also saw him and started running. The speed of the thief is 10 and the speed of the policeman is 11, so we have Have to tell what will be the distance between them after 6 minutes then how much distance will these people cover in 6 minutes subtract 10 from 11 then 1 km is r then if they will walk 1 kilometer in one hour then how much will they walk in 6 minutes 6 divided by 60 How many kilometers will on

e walk in 6 minutes, if I calculate it in meters, how much will I cover, I will have to convert it into 1000, then the distance between them will be so less, if I solve it within 6 minutes, then I will get this value. What was the distance before going 100 meters? There was 200 meters between them. If I reduce the distance of 100 meters in 6 minutes, then how much will be the remaining distance I will have? 200 - 100 and this value will be 100 meters. If you keep a clear mind, then it will be 10

0 meters . This question is very easy, one does not have to put much mind in it. We, a thief, saw a policeman at a distance of 500 meters. The thief starts running. The speed of the thief is R at 17 km. The speed of the policeman is R at 20 km. So we have to tell what will be the distance between them after 8 minutes then you will say sir 20 - 7 that is 3 3 in these 8/6 if the distance becomes so many kilometers then we will reduce the gap of distance and in this I will make it 1000. This value

will come in the meter. If 3 is divided by 20, 20 is divided by 20 then it becomes 50. 8 * 50 becomes 400. What did they do with this distance? If they reduce the distance between them, what will be the remaining distance? If this value is subtracted from this then it will come to me. 100 meters and this is what will happen to this question of mine, the answer will be given, let's move ahead to the next question, now we have a question to be done with a little attention, in the question it is sa

id that a policeman is changing a thief, the speed of the policeman and the speed of the thief. We have been given R at 8 and 6 Kms. The policeman is starting to chase the thief after 10 minutes, so we have to tell after how much distance he will catch the thief. Now how will we do it. Look carefully, the policeman is also there. There is a thief too, he also has speed, the policeman is running after the thief, but what if the policeman catches the thief and starts late by 10 minutes? My policem

an is here and my thief is also here. Now in the beginning, the thief has started running. The policeman is sitting comfortably, drinking tea and having fun. He didn't even pay attention. The thief passed by him and what is a thief? What did the thief do for 10 minutes, he kept running and after 10 minutes the policeman realized that brother, the thief is here, now we have to start catching him, so now the thief is here, if the policeman starts catching him here, then you Tell me what is the dis

tance between them. Within this 10 minutes, you will say, Sir, what is the speed of the thief? What is R at 6 km? According to R at 6 km, how much distance will the thief cover in 10 minutes? It is 10 minutes and I will convert it to 10/60 so it will be 1 km. So here now what is the distance between them? 1 km When the policeman started to catch the thief then at what distance will the policeman catch the thief. Suppose here If both of them will be paid then what do we have to tell, this distanc

e has to be told how much distance the policeman will travel to catch the Chief, so basically we can solve this question directly. If you want to do it with ratio method, then you can do it with ratio method. Yes, it's okay and with the rest of the formula given, I will revise both of them once again. What is the speed of the policeman? I have a pay eight here because both pay the same time. From here till here, if it seems like tee time. In order to escape from the thief, the policeman will als

o run till t time. If time becomes constant then the ratio of their speed will be the ratio of distance. What is the speed of the policeman, a is what is the speed of the thief, then this distance will be The policeman who will cover this distance from me will be 10 ratio, sorry 8 ratio. The policeman who will cover the thief, this will be the ratio. So, the distance I have will be this one, it will be 8 my 6 to it ratio. 2. If rayo is representing 1 kilometer then 1 ray will represent 0.5 kilom

eter or I can say 2 ray is representing 1 kilometer then 8 ray what will it represent intu me four that is 1 in metu ka fo is 8 so No, 4 is 4 kilometers, sorry, you could have also said 0.5, so if 0.5 is 4 kilometers, then the policeman will have to walk 4 kilometers. This is through the diagram. If you want to do it directly with the formula, then you will do it like this. You will say, Sir, you have to find the distance of the policeman. No, I don't know the speed of the policeman in how much

time will he take to catch the thief. Now the speed of the policeman has been fixed. What do we need, R is at 8 km. How much time will he take to catch the thief because the thief had already run away 10 minutes ago. What did the thief get in 10 minutes? If he got extra, then how much distance will the thief cover in 10 minutes? You will say, Sir, how much distance was covered in 10 minutes at the speed of 6 kilometers per hour. 10 times in 6 seconds, I have got this value in kilometers. After t

his, this distance became between the policeman and the thief, when the policeman started catching the thief, how much would be the relative speed of the policeman and the thief, if it would be 8 minus 6, then this became the time I have, how much time would it take for the policeman to catch the speed. Into, time will give my answer, above I will be left with this one and below I will be left with two, this has come 4 km is clear to everyone, next question, I have another question like it says

that there is a thief who committed a crime and ran away Sport There is a security guard at a speed of 12 m from R. He starts chasing after 20 minutes when the thief has already stolen and ran away. It happens many times that there is a security guard and he went to drink tea. Meanwhile, the thief entered and stole and ran away. What is said after 20 minutes when a theft has taken place? When the security guard comes to know that a theft has taken place, he starts running behind him to catch him

. Like we see in general movies too, then we have to tell that if the security guard If he starts running and catches the thief 20 minutes later, what would have been the speed of the security guard? Well, now how can we do it, it is up to you, what logic you want to put in it, okay, one is we ratio method. You can do one, in the basic way which I have been telling you, understand carefully, I have a thief and this is my PU, I consider the security guard as a policeman, the thief will run away f

or 20 minutes, okay, so the thief is here. Now the security guard has come, what will he do in the next 20 minutes, will he catch him? Okay, so how much would the thief have run from here to here, he would have run for 20 more minutes, if this is the entire distance, I assume that there is some distance in. If both of them had covered it together, you would have said, Sir, this distance thief has come to me again. The distance covered by the thief in how many minutes is 20 P 20 The distance cove

red by the thief in 40 minutes is How many minutes is the policeman covering in 20 minutes So I can say that the distance is a constant Capital D So, what is the speed of the thief in 40 minutes? The distance he covered in 40 minutes at the speed of R at 12 meters. What must have been the speed of the police. If I consider the speed of the police as PS, then he covered it within 20 minutes. If I solve this then what value will I get if I spend 20 to 40 minutes then go to R at 12 meters and into

R at 24 meters. What is the speed of the policeman? The question is over. It is asked, okay, don't get confused at all by looking at the units, one way is done, if you wanted to see it through ratio method, then you could have seen it through ratio method also, okay, what would be the other way, sir, which you have been studying the formula for so long. You are writing, what will happen if you use the same, then you can use that also, you will say, Sir, what do I have to do about the policeman,

if you want to tell me the speed, then what is the distance of the policeman, whatever time will be taken in the speed of the policeman. How much time will it take for the police to catch the thief? He has already given us that it will take 20 minutes. Well, what will these 20 minutes be equal to? What will be the distance between these two ? How much distance will the thief have covered in these 20 minutes? 12 meters. But at the speed of R, at 12 meters R into R is 2 AT, this is the distance of

the thief divided by relative speed. What will be the relative speed? We have, suppose the speed of the policeman is x, then x - R at 12 meters, which is the speed of the thief. What did I do? In how much time will the thief be caught? I am giving you the formula for which time is equal to distance. The distance between these two is divided by the relative speed. So I did the same. This policeman will catch the thief after 20 minutes. So 20 minutes have passed. Okay, if the speed of the thief i

s Coming to 12 meters, if you solve from here and find out the value of Okay, the speed of the thief is 80, it was the speed of the policeman and the policeman catches him within 12 minutes, then we have to tell what would have been the speed of the thief, hurry up, how can you do it with the ratio method, with the basic method. If you want to apply the formula then we can also apply the formula directly. Look, if I say that the speed of the thief is 80 to the speed of the policeman, then what w

ill be the speed ratio of the policeman to the speed of the thief. I have 54, I can say, ok. I can consider it as 5x, I can consider it as 4x, okay, we have to tell the value of 4x finally in this question, okay, what is the distance between them, right now it is 0.5 km, right, we have to cover this distance, we will move at relative speed because we will be moving in the same direction. If we are, then what will be the relative speed Who has asked? Kilometer per r in r, kilometer per r in r, so

this is 0.5 meter, minute is minute, so here pe ba 12 divided by 60 to convert to r which will go here and come here pe will be 2.5 x if 2.5 If there is R at km, then I will multiply it by 2.5, then it will come to me, if it comes to 10 km, then the value that will come to me, which will be the speed of the thief, will be R at 10 km. Another way, you can answer this question here. You can also think of this as the speed of the policeman and here I have given the ratio of speed of the thief whic

h is 54 because what is happening here right now is what is the distance between them. If it is 0.5 km then I have The thief will run from here, this is the distance between them, the police will run from here and they will meet here after going somewhere. If we assume destination point or any point, then this will run till t time and this too will run till t time if time becomes constant. What I have here is the ratio of their speed, what will happen to them, the ratio of distance will also be

there and if this ratio of distance is also there then it will be five ratio distance which the police covered and this will be four ratio distance. So that means I can say what is one ratio distance equal to 0.5 km? 1 ratio is equal to 0.5 then what is 4 ratio is equal to 2 km then how much distance did the thief cover? Thief must have covered the distance of 2 kilometers in how many minutes because both of them ran for 12 minutes each. If neither is covering 2 kilometers in 12 minutes, then wh

at will be the speed of the thief? This value will be 60 in 2 diva ba 12 e. So here Se katu pa 5 dani 10 So there is another method, if you want to follow the form of diagram then this can also be seen but this is the general method. Let's move on to the next question. Look at what is given to us in the question. A thief steals an item and escapes. Running at the speed of 15 km R is a thief who steals and starts running from there at the speed of 15 km A. The policeman reaches the crime spot aft

er 4 minutes and immediately starts chasing the thief. Now what happens, say, if there is a theft at my house, I will call the police, like if there is a theft, the police will come and reach my house from the police station, first of all it will take time, so it is 4 minutes, that is the time that the police. The person reaches the crime spot and then starts the chase to catch the thief, that is to say, if I look at this line very carefully, understand this question, it is a bit long question b

ut there is a very small solution to it, so here I have it. What is nearby, he is a thief, this is what I assume, what is the crime spot where the theft is taking place, he stole and what to do for 4 minutes, he starts running as soon as he commits the theft, at a speed of 15 kmph and for 4 minutes After 16 minutes, the policemen come here, it is cleared, now what happens next, after 16 minutes, when the policeman starts changing it, there is still a gap of 200 meters between them, so now what b

ecomes of the situation from here, Thief here But the police is here, he runs for 16 minutes more, so he must have reached somewhere here, the policeman also runs from here to here for 16 minutes and he must be left somewhere and the distance between them, Abhay, you have given it to us. Let's move ahead by 200 meters. It further says that at the distance from the spot of crime, spot of crime, this is our distance from here. If the policeman will catch the thief, then this distance has to be tol

d and I have to tell one thing here. I have to tell what will be the speed of the police, that means I have accepted here that here what will be both of the two, will both of them meet ? Is the question clear? Everyone understood well what all the things are being said in the question. All the things are clear to you through a diagram. Now we can start solving the question. We can have multiple ways to solve it. If you want, here you can calculate the distance first. If you want, here you can ca

lculate the distance of the policeman first. You can calculate the speed, after that you can calculate the distance. I will give you the question in both the ways. I will make a copy of it, after that I will start solving the question for you. Let's do one method first. If I directly give you the form of distance. When I look at it, we saw this thing that when the thief is running away from the first policeman, then how much distance would he have covered within 4 minutes. Within 4 minutes, the

thief will say to you, Sir, the speed is 15 km, the time is 4 minutes, this is in R. If I convert then 4 divided by 60 and this will come to me, I can say kilometer one kilometer or I can say here the distance I have is 1000, okay then the policeman here, loudly say 1000 meters, this has to be changed 16. After traveling both the minutes, it is known that now the gap between them is 200 meters , which means how much distance has been covered in 16 minutes. From the relative speed, you will say,

Sir, if I subtract 200 from Hajj, then we will have This distance of 800 meters was covered with relative speed or the policeman covered 800 meters more within 16 minutes, then the relative speed is If I consider the speed of the policeman as P, then what is the speed of the thief, here I have 15. If we go for how many minutes at this speed, if we go for 16 minutes, that is, 16 divided by 60, then how much distance will be covered, we have 800 meters, I can multiply this by 1000 to convert it in

to kilometers, then from here I will get the speed of the policeman. I can take it out, you will say Sir, two zeros will be deducted from two zeros, if I cut from at, if I cut from tutu, then 30 will come and this will be 30/1, 3 will come and 15 will be added there, then this will become 18 km. What is the speed of the policeman here? If I see the speed of the policeman among the four options, then only option number D is satisfying, so this can be my correct one, so if you want to calculate th

e total distance then do so, otherwise my work here is over, the question should be solved . Total distance traveled after how much distance How will we find out who this policeman is and whether he will catch the thief? You will say, Sir, the speed of the policeman has been found. We know the distance, how far ahead the thief was at the time of starting, so you apply the same formula which you tell at the time of starting. The total distance that the policeman would have to travel from here to

here to catch the thief would be the time taken by the policeman to catch the thief. How much was the distance in between, was it 1000 meters or 1 kilometer, I can say. What is the relative speed? We just saw that I was coming at only 15 kms, so the relative speed was, subtract 15 from 18 and the time became what is the speed of the policeman at 18 km, so this is The policeman must have walked a total of 6 kilometers to catch the thief. Our question has ended here. I hope this is a general metho

d. You all must have understood it well. My question is now over. Well, if I look at it in another way, what can they see? To answer this question, you can also understand in this way that brother, how much was the gap between them in the beginning, we just figured out that sir, this is a gap of 1000 meters because In 4 minutes, the policeman and sorry thief covered the distance of 1000 meters. After both of them walked for 16 minutes, the gap left between them was 200 meters, so I can say how m

uch should be the gap which is decreasing due to relative speed in 16 minutes. If we subtract 200 from 1000 then the distance of 800 meters is decreasing from the relative speed. How much distance do we have to reduce in 16 minutes from the relative speed? We have to reduce the total distance by 1000 meters from the relative speed so that both get matched. So if Let me see, from here I have to make it 1000 meters, so what do I have to do to make 1000 meters distance, divided by 800 into it, I wi

ll make 1000 or 1000 is made, I divided by this, I got one, or you are here. But they say, Sir , if you divide 800 by 16, then in this number of minutes, the distance of one meter will be covered with relative speed and if I want to make 1000, then you will multiply by 1000, then what will he do within so many minutes, basically the thief will be caught by the police. Isn't it so if I solve it then from here it will be 50 and from here if I say 20 then total it will take 20 minutes for the polic

e to catch the thief. Good total distance. If I am asked at what distance the police caught the thief then if Should I look from the beginning or if I say let's catch the thief from here in four minutes, the policeman has already gone to the Hajj meter, so now he will run for 20 more minutes because when the policeman here starts chasing the thief, then within 20 minutes he will run. After this process ends, how much distance will the thief cover in 20 minutes? The total distance that will come

to me will be 1 km plus the speed of Tor is 15 km in 20 minutes. Convert 20 parts to 60 R. If I cut it here then it will come to 5 and then it will come to 6 so the total is 6 kms from the starting. If the thief is caught after 6 kms then what is the total distance with me. 6 kms. If I see four options then if this comes from here then this is my answer. Now he has asked us to tell him the speed of the policeman, brother, what will happen if you say sir, we will find out the speed of the policem

an, what is the total distance, 6 kilometers, in how much time is the policeman covering it, because he ran for 20 minutes and then he became a thief. If I cover 20 minutes, if I convert 20 minutes into R, it will come to 60. If I solve the police speed, it will come to 18 kilometers. This can also be seen in this way. You have both the methods, one I told you about and another one. The method is this, another question of the same type was asked in your exam, so let us see what is given here. It

is said that a thief committed a theft and started running away at the speed of 20 km. The policeman comes to the spot. After 6 minutes, he follows him and after 24 minutes, when the police man is chasing the thief, then what is the gap between them? If it is 400 meters, then we have to tell at what distance from the spot of crime. The Policeman Catch up with the Thief and What is the Speed ​​of the Policeman If we have to tell both the things then how will we solve them? Now if you look at all

the four options then what is the distance of all four, it is different but the speed of the policemen is same at two places. First, if I find out the distance, then things will be done easily for me. This is a very similar question, so how will you do it, tell me, I will make a diagram or else directly, you can think of it a little, we are a thief running at a speed of 20 km per hour. If the policeman starts changing it after 6 minutes, then how much will the thief have fled? 20 * 6 divided by

60 and this one Value will come to me if I have 2 km then the policeman will have to run 2 km extra to catch the thief in 24 minutes or when the policeman runs after the thief then the gap between them remains only 400 meters. Ok so if Let us talk, if the gap remains 400 meters, then how much gap is covered? If I subtract 400 from 2 km, then the gap of 1600 meters is covered. Within how many minutes, how much gap do we have to cover. Within 24 minutes, we have to cover 2 km. Then there will be

a meeting between the thief and the police, the police will catch the thief, then if it has to be made 2 kilometers i.e. 2000 meters, then you will say sir, what will happen here, divide 1600 in 24 and multiply it by 2000. So many minutes, if I solve from here, I will have 16 here, these two zeros will be deducted from two two zeros, this will be five, this will be four, if this is deducted from four, then six more 6 5 30 minutes What is the police within 30 minutes? Will he catch the thief? Thi

s question could also have been made in the exam and this question could have been made directly in the exam. You could have taken the time from here. In how many minutes, what will the policeman do? Will he catch the thief when he starts running? We have been asked about the total distance when the thief first When he started running, how much did the thief run away because we do not have the speed of a policeman. If we have the speed of a thief, we will calculate it in thief's terms. In how ma

ny minutes did the thief run away from the crime spot at the start? At 20 km, he ran at the speed of R for 6 minutes. After that, when the police started catching him, what would I have got? So the thief covered this distance first. When the police started catching him, how many minutes did it take for the thief to run away? 30 minutes more and the thief would have run away from the police for 30 more minutes. Before being caught, he ran for 30 minutes at a speed of 20 and then you can divide 30

by 60 like this. Otherwise, if you wanted, you could have calculated the total time. How much did the thief run? Total: 30 minutes after the police and 6 minutes before the police, so the total was 36 minutes. If I ran, I can say 36 minutes at a speed of 20, which means 36/60 and how much distance had I covered and it came to 12 12 km. 12 km ahead of Crime Sport, police caught the thief. If you look at all four options, then go with option B. Will go away, if you have to tell the speed of the p

oliceman, then you will say sir, what is the distance, 12 km is how many minutes, if the policeman ran for half an hour, then 30 minutes, then I will convert 30 minutes into R, then 30 times 60, then it comes to R at 24 km. It is clear to everyone, I am asking you one more extra question so that you do not face any problem. You do not have CGL 2023 in the question related to thief, but it was also asked in the crash course given by me and anyway you should come and see the question. It is said t

hat a policeman sees a thief at a distance of 700 meters and starts changing him. The policeman can run 4.7 kilometers within 11 minutes and the thief can run 4.7 kilometers within 34 minutes. Okay, so tell us. How much distance will be traveled by the thief before being caught? This is a good question. Do it carefully, only then you will be able to clear the basic concepts. Now understand this question carefully. If I have to do it, then how can I do it? I am this, I have a policeman, he is a t

hief, what is the distance given between them, you have given 700 meters, the policeman starts catching the thief, what is the speed of the policeman, you have given us, 4.7 kilometers in how many minutes, in 11 minutes, so bye 11 I can do more minutes per kilometer, this is the speed of the policeman, what is the speed of the thief, 4.7 kilometers in 34 minutes, so by 34 minutes, I have done more minutes, there is no problem here, the speed of the policeman has also come, the speed of the thief

has also come. Now we have to tell how much distance the thief will travel before being quoted as a thief because the thief is starting from here, so this one has to tell the distance the thief will travel before you say to me, Sir, the policeman is starting from here. The thief is moving from here, but the time taken by the policeman to ask from here to here will be the same as that taken by the thief to ask from here to here. If time becomes constant, then what will happen to me. If the dista

nce becomes directly proportional to speed, then the police If I calculate the ratio of the driver's speed and the thief's speed, it is 4.7 units per minute per 11 km, but right now we are looking at the ratio, there is no need to go beyond that, what are the units given, it is 4.7 units per minute. 34 is kilometer per minute, so you will see that the ratio of speed that we have will be the same ratio of distance, so if this is the ratio of speed, then the ratio of distance will also be the same

. If I solve it, then you will see that these kilometers and all these are cut. Gone 4.7, cut 34, I cross multiplied it by 11, what happened to them, what is the ratio of distance, so within a constant time, how much will the policeman go here, 34 ratio will go, then the thief I have, how much ratio will he go, he will go only 11 ratio. So what is their difference? 34 - 11 This value will come to me: 203 rayo 23 represents 700 meters, so 1 700 / 23 and what else do we have to tell? We have to te

ll how much distance the thief traveled. That is 11 . Rayo, so what we will do in this is multiply by 11 and this will be my answer. If you look carefully, what answer can I have in the four options, this is 400 meters, 470 is 334 and this is 4, okay you will see which is 23. It is 11 * 223, it is 22, so the value will be a little more than two, in Dino Minette, this value will be a little less than half of 700, so what can be the value, a little less than 350, 34.7, this can be this in If I can

not get the correct options in all three then this is my answer. Here you can find your answer by using the ratio concept. When we are asked about the distance, you can apply the ratio concept directly. If you wanted, you could have done it from basic as well. What would have been your common things, had they come and gone ahead and got cut, it would not have made any difference, we will move ahead, now this marks the end of this video, I hope this video is useful to all of you , you would have

got to learn a lot and Now you will be able to solve all the questions related to thief and police very easily. By twisting the language, SSC can create as many questions as you want. You will have to think at the same time as to what has been changed inside the question and then you will have to solve it. You will have to do the rest if you feel that your approach is improving due to my teaching, you are getting benefit and you feel that there is a lot of deficiency in your preparation or you n

eed to improve and you need to know everything in detail. If you want to study all the concepts type wise then you can join RB Officer Batch, in which all my classes for Maths are given, after that Reasoning is given by different teachers, English is different, there are different teachers for GK and GS, they also have demo classes. You can do it on youtube0, all the videos are already available for your upcoming examination so that you can do your preparation in minimum time. We try to provide

all types of PDFs so that you do not face any problem and also if you have free time. I think if I want to study only Maths and Reasoning then you will get this complete course of Maths along with which we have kept the Reasoning course free and also if you want you can enroll in different courses of different subjects. Are available, like skill in steno is stenography, its course is also available, MTS JD, you will get courses for all the exams, syllabus is almost same, everything is included i

n officer batch, test series is also included in it, rest if you are individual. If you need help in any particular subject then you can purchase those courses. This is what I will take from you in this video. Bye everyone take care, have a nice day and Jai Hind.